`(b+c)/a=(cosB+cosC)/(1-cosA)`

(a+b+c)(cosA+cosB+cosC)

In DeltaABC, show that (1-cosA+cosB+cosC)/(1-cosC+cosA+cosB)=tan(A/2) cot (C/2).

In DeltaABC , prove that: (c-bcosA)/(b-c (cosA))=(cosB)/(cosC)

If in a triangle ABC, (cosA)/a=(cosB)/b=(cosC)/c ,then the triangle is

If in a Delta A B C ,(cosA)/a=(cosB)/b=(cosC)/c , then find the measures of angles A ,\ B ,\ Cdot

In a triangle ABC, if (cosA)/a=(cosB)/b=(cosC)/c and the side a =2 , then area of triangle is

With usual notations, if in a triangle A B C(b+c)/(11)=(c+a)/(12)=(a+b)/(13) , then prove that: (cosA)/7=(cosB)/(19)=(cosC)/(25)

With usual notion, if in triangle A B C , (b+c)/(11)=(c+a)/(12)=(a+b)/(13),t h e np rov et h a t (cosA)/7=(cosB)/(19)=(cosC)/(25)

a(cosC-cosB)=2(b-c)cos^2A/2

In any DeltaABC , prove that (1+cos(A-B)cosC)/(1+cos(A-C)cosB)=(a^(2)+b^(2))/(a^(2)+c^(2))