What will be the product of zeroes of the quadratic equation `3x^2 + 2x - 5 `?

Options

A. `3//5`
B. `-5//3`
C. `2//5`
D. `-5//2`

Answer

To find the product of the zeroes of the quadratic equation \(3x^2 + 2x - 5\), we can use the relationship between the coefficients of the quadratic equation and its zeroes.

### Step-by-step solution:

1. **Identify the coefficients**:
The standard form of a quadratic equation is \(ax^2 + bx + c = 0\). For the given equation \(3x^2 + 2x - 5\), we identify:
- \(a = 3\)
- \(b = 2\)
- \(c = -5\)

2. **Use the formula for the product of the zeroes**:
The product of the zeroes of a quadratic equation is given by the formula:
\[ \text{Product of zeroes} = \frac{c}{a} \]

3. **Substitute the values of \(c\) and \(a\)**:
Now, substitute the values we identified:
\[ \text{Product of zeroes} = \frac{-5}{3} \]

4. **Final result**:
Therefore, the product of the zeroes of the quadratic equation \(3x^2 + 2x - 5\) is:
\[ -\frac{5}{3} \]