Transverse velocity
(A)`hatr` (B)`vecr` (C)`theta` (D)`rhat(theta)`

Let -> a and -> b be two unit vectors and is the angle between them. Then -> a+ -> b is a unit vector if (A) theta=pi/4 (B) theta=pi/3 (C) theta=pi/2 (D) theta=(2pi)/3

Two bullets are fired at angles theta and 90-theta the ratio of their time of flights is (A) Tan theta:1 (B) 1:Tan theta (C) Tan^(2)theta:1 (D) 1:Tan^(2)theta

Find te valueof 1-2sin^2theta + sin^4theta . (A) sin^4theta (B) cos^4theta (C) tan^4theta (D) sec^4theta

If sec theta+tan theta=1, then one root of the eqection a(b-c)x^(2)+b(c-a)x+c(a-b)=0 is (A) tan theta(B)sec theta(C)cos theta(D)sin theta

The value of (1)/(8)(3-4cos2 theta+cos4 theta) is (A)cos4 theta(B)sin4 theta(C)sin^(4)theta(D)cos^(4)theta

int e^(tan theta)(sec theta-sin theta)d theta is equal to: (A)-e^(tan theta)sin theta+c(B)e^(tan theta)sin theta+c(C)-e^(tan theta)sec theta+c(D)e^(tan theta)cos theta+c

(sin theta)/(1-cot theta)+(cos theta)/(1-tan theta) is equal to (a) 0 (b) 1(c)sin theta+cos theta(d)sin theta-cos theta

A body is projected obliquely from the ground with a speed 'u' and at an angle "'theta with the horizontal.It's velocity at the maximum height is (A) zero (B) u sin theta,(C) u cos theta (D) u

intsecx/(sqrt(sin(2x+theta)+sin theta))dx(AA x,theta in(0,(pi)/(2))) (A) sqrt(3(tan x sec theta+tan theta sec theta))+c (B) sqrt(2(tan x sec theta+tan theta sec theta))+c (C) sqrt(5(tan x sec theta-tan theta sec theta))+c (D) sqrt((tan x sec theta-tan theta sec theta))+c

(sin3 theta+sin5 theta+sin7 theta+sin9 theta)/(cos3 theta+cos5 theta+cos7 theta+cos9 theta) is equal to tan3 theta(b)cot3 theta(c)tan6 theta(d)cot6 theta