`(x^3y^3+xy)dx=dy`

(x^2y^3+xy)dy=dx

Solve the following differential equation: (x^3-2y^3)dx+3xy^2\ dy=0

(x^3+3x y^2)dx+(y^3+3x^2y)dy=0

Suppose a solutions of the differential equation (xy^3 + x^2y^7) dy/dx =1 satisfies the initial conditions y(1/4)=1. Then the value of dy/dx when y = -1 is

The solution of the differential equation x=1+x y(dy)/(dx)+(x^2y^2)/(2!)((dy)/dx)^2+(x^3y^3)/(3!)((dy)/(dx))^3+... i s

Solve the following differential equation: (x^2-2x y)\ dy+(x^2-3xy+2y^2)dx=0

Show that (3xy + x^(2)) dy + (y^(2) + xy)dx = 0 is homogeneous differential equation. Also find its general solution.

Solve the differential equation: (x+3y^2)(dy)/(dx)=y

The solution of the differential equation (xy^4 + y) dx-x dy = 0, is

The solution of the differential equation (xy^4 + y) dx-x dy = 0, is