`y(xy+e^x)dx-e^xdy=0`

The solution of y(2xy+e^x)dx-e^xdy=0 is (A) x^2+ye^(-x)=C (B) xy^2+e^(-x)=C (C) x/y+e^(-x)/x^2=C (D) x^2+e^x/y=C

y(2x y+e^x)dx-e^x dy=0

Solution of the differential equation y(a x y+e^x)dx-e^x dy=0 where y(0)=1 is

y(x^(2)y+e^(x))dx-e^(x)dy=0

The general solution of the differential equation y(x^(2)y+e^(x))dx-(e^x)dy=0 , is

Solve: y(1+xy)dx-xdy=0

(y^2e^x+2xy)dx-x^2dy=0

y = f(x) which has differential equation y(2xy + e^(x)) dx - e^(x) dy = 0 passing through the point (0,1). Then which of the following is/are true about the function?

The solution of e^(x((y^(2)-1))/(y)){xy^(2)dy+y^(3)dx}+{ydx-xdy}=0 , is

The solution of the differential equation (dy)/(dx) = e^(x-y) (e^(x)-e^(y)) is