`(1+xy)dx=x/ydy`

Solve: y(1+xy)dx-xdy=0

Solve : (dy)/(dx)=1-xy+y-x

The solution of the differential equation (ydx-xdy)/(xy)=xdx+ydy is (where, C is an arbitrary constant)

Find the particular solution of the differential equation (1-y^2)(1+logx)dx+2x ydy=0, given that y=0 when x=1.

Solve the following differential equations (dy)/(dx)=(xy+y)/(xy+x)

The equation of the curve satisfying the differential equation xe^(x)sin ydy-(x+1)e^(x) cos ydx=ydy and passing through the origin is

Solve the following differential equation : (sqrt(1+x^2+y^2+x^2y^2))dx+x ydy=0

y(xy+1)dx+x(1+xy+x^(2)y^(2))dy=0

The solution of the ( dy )/(dx) = (xy+y)/(xy+x) is :

if y= (sin ^(-1)x)/(sqrt(1-x^2)) then prove that (1-x)^2) .d/dx=xy+1