`log(x+3)-log(x)=log2`

Solve the following equation for x: 9^(log_3(log_2x))=log_2 x- (log_2 x)^2+1

The sum of all positive numbers x such that (log_(x)3)(log_(x) 9)+2=5 log_(x) 3 is a value between

Solve : log_(3)x . log_(4)x.log_(5)x=log_(3)x.log_(4)x+log_(4)x.log_(5)+log_(5)x.log_(3)x .

If log_(2)(log_(2)(log_(3)x))=log_(3)(log_(3)(log_(2)y))=0 , then x-y is equal to :

If the function f(x)=log(x-2)-log(x-3) and g(x)=log((x-2)/(x-3)) are identical, then

If log_(2)(log_(4)(x))) = 0, log_(3)(log_(4)(log_(2)(y))) = 0 and log_(4)(log_(2)(log_(3)(z))) = 0 then the sum of x,y and z is-

If higher powers of x^(2) are neglected, then the value of log(1+x^(2))-log(1+x)-log(1-x)=

The domain of the function f(x) = log_(3/2) log_(1/2)log_pi log_(pi/4) x is

Solve the equation: 2log_(3)x+log_(3)(x^(2)-3)=log_(3)0.5+5^(log_(5)(log_(3)8)

Solve for x : 3^(log x)-2^(log x) =2^(log x+1)-3^(log x-1)