1.`(1+x^2)dy/dx+2xy-x^3=0`

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(1-x^(2))(dy)/(dx)-2xy=x-x^(3)

IF of the following differential equations. (1-x ^2)(dy //dx) + 2xy = x ( 1- x^2 ) ^(1//2)

(1+x^(2))(dy)/(dx)-2xy=(x^(2)+2)(x^(2)+1)

(1-x^(2))(dy)/(dx)-xy=1

(1-x^(2))(dy)/(dx)+xy=ax

x^2(dy/dx)^2-2xy dy/dx+2y^2-x^2=0

Solve: (1+x^2)(dy)/(dx)+2xy=cosx

(1+x^(2))(dy)/(dx)+2xy=(1)/(1+x^(2));y=0 if x=1

(1 + x^(2)) (dy)/(dx) + 2xy = 4x ^(2) , given that y = 0 , when x =0

The general solution of the DE (1+ x ^(2)) dy - xy dx = 0 is