` tan theta / {(tan theta +2)(tan theta +3)} `

Solve tan theta + tan 2 theta + tan theta * tan 2 theta * tan 3 theta=1

If: tan theta + tan 2theta = tan 3theta , then: theta =

Prove that (tan 5theta + tan 3theta)/(tan 5theta - tan 3theta) = 4 cos 2theta cos 4theta

If: tantheta + tan 2theta + tan 3theta = tan theta.tan2theta.tan 3theta , then: theta =

f theta_(1),theta_(2),theta_(3),theta_(4),theta_(5)in(0,(pi)/(2)), satisfying tan theta_(1)tan theta_(2)tan theta_(3)tan theta_(4)tan theta_(5)=1 then maximum_(2 value of )theta_(3)tan theta_(4)cos theta_(5) is cos theta_(1)cos theta_(2)cos theta_(3)cos theta_(4)cos theta_(5) is

If cos(theta_(1)-(pi)/(4))+sin(theta_(2)+(pi)/(2))+cos(theta_(3)-(pi)/(3))+3=0 , then tan theta_(1)+tan theta_(2)+tan theta_(3) is: (where theta_(1),theta_(2),theta_(3)in(0,2 pi))