`(cos theta*sin^(2)theta)/(sin theta*cos^(2)theta)=?`

Inverse of the matrix [(cos 2 theta,-sin 2theta),(sin 2 theta, cos 2theta)] is

Prove the following identity: ((1)/(sec^(2)theta-cos^(2)theta)+(1)/(cos ec^(2)theta-sin^(2)theta))sin^(2)theta cos^(2)theta=(1-sin^(2)theta cos^(2)theta)/(2+sin^(2)cos^(2)theta)

Inverse of the matrix [{:(cos 2 theta, -sin 2 theta),(sin 2 theta, cos 2 theta):}] is

if A=[{:(costheta,sin theta ),(-sin theta,costheta):}] , then show that : A^(2)=[{:(cos2theta,sin2theta),(-sin2theta,cos2theta):}]

(2sin theta*cos theta-cos theta)/(1-sin theta+sin^(2)theta-cos^(2)theta)=cot theta

The value of (cos^6 theta+sin^6 theta+ 3sin^2 theta cos^2 theta)/(cosec theta sec theta(sin theta+cos theta-1)(sin theta+cos theta+1)) is : (cos^6 theta+sin^6 theta+ 3sin^2 theta cos^2 theta)/(cosec theta sec theta(sin theta+cos theta-1)(sin theta+cos theta+1)) का मान ज्ञात कीजिए?

Prove that :(sin theta cos(90^(0)-theta)cos theta)/(sin(90^(0)-theta))+(cos theta sin(90^(0)-theta)sin theta)/(cos(90^(@)-theta))=1csc^(2)(90^(@)-theta)-tan^(2)theta=cos^(2)(90^(@)-theta)+cos^(2)theta

((sin^(3)theta+cos^(3)theta)/(sin theta+cos theta)+(cos^(3)theta+sin^(3)theta)/(cos theta+sin theta))=?