`A=[[cos theta,0,sin theta],[0,1,0],[sin theta,0,cos theta]]`

Find the inverse of A=[[cos theta,-sin theta,0sin theta,cos theta,00,0,1]]

If A= [[cos theta,-sin theta],[sin theta,cos theta]] ,then Adj A is (a) [[cos theta,-sin theta],[cos theta,sin theta]] (b) [[1,0],[0,1]] (c) [[cos theta,sin theta],[-sin theta,cos theta]] (d) [[-1,0],[0,-1]]

cos m theta-sin n theta=0

If I=[[1,0] , [0,1]] and B=[[0,1] , [-1,0]] and C=[[cos theta, sin theta] , [-sin theta, cos theta]] then C=

If cos2theta=0 , then |(0,costheta,sin theta),(cos theta, sin theta, 0),(sin theta, 0, cos theta)|^(2) is equal to…………

What is the inverse of the matrix A= ({:(cos theta, sin theta ,0),(- sin theta, cos theta,0),(0 , 0, 1):})

If f(theta)=[(cos theta, -sin theta,0),(sin theta, cos theta, 0),(0,0,1)] then {f(theta)^(-1)} is equal to

If cos2 theta=0 If det[[0,cos theta,sin thetacos theta,sin theta,0sin theta,o,cos theta]]^(2)

If I= [{:(,1,0),(,0,1):}], J=[{:(,0,1),(,-1,0):}]and B=[{:(,cos theta,sin theta),(,-sin theta,cos theta)]:}"then B"=