`(y(xy+e^x)dx-e^xdy)/y^2=0`

y(2x y+e^x)dx-e^x dy=0

The solution of y(2xy+e^x)dx-e^xdy=0 is (A) x^2+ye^(-x)=C (B) xy^2+e^(-x)=C (C) x/y+e^(-x)/x^2=C (D) x^2+e^x/y=C

y(x^(2)y+e^(x))dx-e^(x)dy=0

Solution of the differential equation y(a x y+e^x)dx-e^x dy=0 where y(0)=1 is

(y^2e^x+2xy)dx-x^2dy=0

The general solution of the differential equation y(x^(2)y+e^(x))dx-(e^x)dy=0 , is

y = f(x) which has differential equation y(2xy + e^(x)) dx - e^(x) dy = 0 passing through the point (0,1). Then which of the following is/are true about the function?

Solve y e^(x/y)dx=(x e^(x/y)+y^2)dy ,(y!=0)dot

Solve the differential equation y e^(x/y)dx=(x e^(x/y)+y^2siny)dy(y!=0)

Solve the differential equation y e^(x/y)dx=(x e^(x/y)+y^2)dy(y!=0)