`xy^2dx+(y+1)e^-xdy=0`

y^2dx+(x^2-xy+y^2)dy=0

(y^2e^x+2xy)dx-x^2dy=0

Solve: x^2dy-y^2dx+xy^2(x-y)dy=0

The solution of y dx-xdy+3x^2 y^2 e^(x^3) dx = 0 is

(1 + xy) ydx + (1-xy)xdy = 0

The solution of y(2xy+e^x)dx-e^xdy=0 is (A) x^2+ye^(-x)=C (B) xy^2+e^(-x)=C (C) x/y+e^(-x)/x^2=C (D) x^2+e^x/y=C

If any differentisl equation in the form f(f_(1)(x,y)d(f_(1)(x,y)+phi(f_(2)(x,y)d(f_(2)(x,y))+....=0 then each term can be intergrated separately. For example, intsinxyd(xy)+int((x)/(y))d((x)/(y))=-cos xy+(1)/(2)((x)/(y))^(2)+C The solution of the differential equation (xy^(4)+y)dx-xdy=0 is

y = f(x) which has differential equation y(2xy + e^(x)) dx - e^(x) dy = 0 passing through the point (0,1). Then which of the following is/are true about the function?

If a conic passes through (1, 0) and satisfies differential equation (1 + y^2) dx - xy dy = 0 . Then the foci is:

Solve: y^2dx+(x^2+xy+y^2)dy=0