`dy/dx+y=1(yne1)`

Find dy/dx if y=(x-1)^(1/2)

find dy/dx if y=(1-x)/(1+x)

Solve the initial value problem: y-x(dy)/(dx)=2(1+x^2(dy)/(dx)),\ y(1)=1

Find the order and degree of the following differential equations. i) (dy)/(dx)+y=1/((dy)/(dx)) , ii) e^(e^(3)y)/(dx^(3))-x(d^(2)y)/(dx^(2))+y=0 , iii) sin^(-1)(dy)/(dx)=x+y , iv) log_(e)(dy)/(dx)=ax+by v) y(d^(2)y)/(dx^(2))+x((dy)/(dx))^(2)-4y(dy)/(dx)=0

(dy)/(dx) =-(y+sinx)/(x) satisfying condition y(0)=1

Solve the differential equation: (i) (1+y^2) + ( x - e^(tan^-1 y) ) dy/dx = 0 (ii) x dy/dx + cos^2 y = tan y dy/dx

The solution of (dy)/(dx)-y=1, y(0)=1 is given by

Solve: (i) sin^(-1)((dy)/(dx))=x+y (ii) (dy)/(dx)=cos(x+y) (iii) (dy)/(dx)=(4x+y+1)^2

dy/dx cos(x-y) = 1

Solve: (dy)/(dx)=1/(y^2+siny)