`x(y^2-1)dx-y(x^2-1)dy=0`

Solve the differential eqaution x(1+y^2)dx-y(1+x^2)dy=0, given that y=0 when x=1

The solution of the equation (x^2y+x^2)dx+y^2(x-1)dy=0 is given by

Solve the following differential equations x^(2)(y+1)dx+y^(2)(x-1)dy=0

Solve the following differential equations: (1+x)(1+y^2)dx+(1+y)(1+x^2)dy=0

The general solution of the differential equation (2x-y+1)dx+(2y-x+1)dy=0 is -

Solve the differential equation x (1 + y^2) dx - y (1 + x^2) dy = 0

The solution of the differential equation {1/x-y^(2)/(x-y)^(2)}dx+{x^(2)/(x-y)^(2)-1/y}dy=0 is

If y=x^x prove that (d^2y)/(dx^2)-1/(y)(dy/dx)^2-y/x=0

Show that the general solution of the differentia equation (dy)/(dx)+(y^2+y+1)/(x^2+x+1)=0 is given by x+y+1=A(1-x-y-2x y) where A is a parameter.

If y="cosec"^(-1)x ,\ \ x >1 , then show that x(x^2-1)(d^2y)/(dx^2)+(2x^2-1)(dy)/(dx)=0 .