`(sqrt 5 + sqrt 2)^2` =?

Rationalize the denominator 1/(sqrt 3 - sqrt 2) - 2/(sqrt 5 - sqrt 3) + 3/(sqrt 5 - sqrt 2)

2sqrt5 - sqrt5 = sqrt5

Simplify the following expressions: (i)\ (sqrt(3)+\ sqrt(7))^2 (ii)\ (sqrt(5)-sqrt(3))^2 (iii)\ (2sqrt(5)+3sqrt(2))^2

Simplify the following expressions: (i) (3+sqrt(3))\ (3-sqrt(3)) (ii) (sqrt(5)-\ sqrt(2)\ )(sqrt(5)+sqrt(2))

State, whether the following numbers are rational or not : (i) (2+sqrt(2))^(2)" (ii) "(5+sqrt(5))(5-sqrt(5)) (iii) (sqrt(7)/(5sqrt(2)))^(2)

Simplify the following expressions: (i) (sqrt(3)+sqrt(7))^2 (ii) (2sqrt(5)+3sqrt(2))^2

The radius of the circle passing through the points (1, 2), (5, 2) and (5, -2) is : (A) 5sqrt(2) (B) 2sqrt(5) (C) 3sqrt(2) (D) 2sqrt(2)

If the vertices of a triangle are (sqrt(5,)0) , ( sqrt(3),sqrt(2)) , and (2,1) , then the orthocentre of the triangle is (a) (sqrt(5),0) (b) (0,0) (sqrt(5)+sqrt(3)+2,sqrt(2)+1) (d) none of these

If x= ( sqrt5- sqrt3)/ ( sqrt5+ sqrt3) and y= ( sqrt5+ sqrt3)/( sqrt5- sqrt3) find the value of x^(2) + y ^(2)

Find x and y if: (3/sqrt(5) x-5)+i2 sqrt (5) y= sqrt(2)