The value of `(m+n)^2+(m-n)^2` is:

The value of (2^(m).3^(2m-n).5^(m+n+3).6^(n+1))/(6^(m+1).10^(n+3).15^(m))

If (m-n)/(n)=(4)/(9) , what is the value of (n)/(m) ?

If m = root(3)(15) and n = root(3)(14) , find the value of m - n - (1)/(m^(2) + mn + n^(2))

If m=root3(125) and n=root3(64) , find the value of m-n-(1)/(m^(2)+mn+n^(2)) .

The value of .^(n)C_(1)+.^(n+1)C_(2)+.^(n+2)C_(3)+"….."+.^(n+m-1)C_(m) is equal to a. .^(m+n)C_(n) - 1 b. .^(m+n)C_(n-1) c. .^(m)C_(1) + ^(m+1)C_(2) + ^(m+2)C_(3) + "…." + ^(m+n-1)C_(n) d. .^(m+n)C_(m) - 1

Find the value of m and n : if : ( 3+ sqrt2 )/( 3- sqrt2) = m + n sqrt2

Find the values of m and n if : 4^(2m)=(root(3)(16))^(-(6)/(n))=(sqrt(8))^(2)

If mgt0, ngt0 , the definite integral I=int_0^1 x^(m-1)(1-x)^(n-1)dx depends upon the values of m and n is denoted by beta(m,n) , called the beta function.Obviously, beta(n,m)=beta(m,n) .Now answer the question:The integral int_0^(pi/2) cos^(2m)theta sin^(2n)theta d theta= (A) 1/2beta(m+1/2,n+1/2) (B) 2beta(2m,2n) (C) beta(2m+1,2n+1) (D) none of these

Let log x= 2m - 3n and log y = 3n - 2m Find the value of log (x^(3) /y ^(2)) in terms of m and n.

Find the values of m and n, in each case, If: (-6, n+2) on reflection in origin gives (m+3, -4)