Recommended Questions
- समाकलन करें। </br> int0^(pi/2) e^x sin xdx
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- Evaluate: int(-pi)^pi(xsinx dx)/(e^x+1)
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- int (0) ^ (pi) e ^ (sin ^ (2) x) cos ^ (3) xdx
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- int(0)^(pi//2) e^(sin)x cos xdx is equal to
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- "int0^pi cos^(2)xdx
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- "int0^pi sin^(2)xdx
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- int0^(pi/2) sin^3 xdx
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- int0^(pi) xcos^2 xdx
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- int0^(pi//2)(sin^(3//2)xdx)/(cos^(3//2)x + sin ^(3//2)x) का मान है
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