solve : `(2tan30^`degree`)/(1+tan^2 30^degree)`

solve : (2tan30^@)/(1+tan^2 30^@)

Choose the correct option and justify your choice : (i) (2tan30^@)/(1+tan^2 30^@) (a)\ sin 60^@ (b)\ cos 60^@ (c)\ t a n 60^@ (d)\ sin 30^@

Find the vlaue of (2tan30^(@))/(1-tan^(2) 30^(@)) .

Solve (tan3x-tan2x)/(1+tan3xtan2x )=1

Verify that: sin60o=(2tan30o)/(1+tan^2 30o)=(sqrt(3))/2 (ii) cos60o=(1-tan^2 30o)/(1+tan^2 30o)=1/2

Angle between the line (x+1)/1=y/2=(z-1)/1 and a normal to plane x-y+z=0 is (A) 0 degrees ( B) 30 degrees (C) 45 degrees (D) 90 degrees

find the value of x where triangle ,angle =a=30degree and angle=b=80degree

Prove that : tan(2 times 30^(@))=(2tan30^(@))/(1-tan^(2)30^(@))

Prove that : tan(2 times 30^(@))=(2tan30^(@))/(1-tan^(2)30^(@))

Verify that sin60^(@)=(2tan 30^(@))/(1+tan^(2)30^(@))