Solve `cos^(4)theta-sin^(4)theta=cos^2theta`

Solve 7cos^(2)theta+3sin^(2)theta=4

The value of cos^(4)theta+sin^(4)theta-6cos^(2)theta is cos2 theta (b) sin2 theta(c)cos4 theta(d) none of these

Solve: 7cos^(2)theta+3sin^(2)theta=4

The value of (2(sin^(6)theta+cos^(6)theta)-3(sin^(4)theta+cos^(4)theta))/(cos^(4)theta-sin^(4)theta-2cos^(2)theta) is :

solve 7cos^(2)theta+3sin^(2)theta=4

Prove that (cos^(4)theta-sin^(4)theta)/(cos^(2)theta-sin^(2)theta)=1

sin^(4)theta+cos^(4)theta=1-2sin^(2)theta cos^(2)theta

Solve: 4sin^(4)theta+cos^(4)theta=1

Prove that sin^(4)theta-cos^(4)theta=sin^(2)theta-cos^(2)theta