If one mole of monoatomic gas is mixed with one mole of a diatomic gas, Then the equivalent value of γ for the mixture will be (vibration mode neglected)

When one mole of monoatomic gas is mixed with one mole of triatomic gas, then the equivalent value of gamma for the mixture will be (vibration mode neglected)

When 1 mole of monoatomic gas is mixed with 2 moles of diatomic gas, then find gamma for the mixture of gases.

If one mole of a monatomic gas (gamma=5/3) is mixed with one mole of a diatomic gas (gamma=7/5), the value of gamma for mixture is

If one mole of a monatomic gas (gamma=5/3) is mixed with one mole of a diatomic gas (gamma=7/5), the value of gamma for mixture is

For one mole of a diatomic gas gamma is equal to

One moles of a monatomic gas is mixed with three moles of a diatomic gas. The molar specific heat of the mixture at constant volume is

One mole of a mono-atomic ideal gas is mixed with one mole of a diatomic ideal gas. The molar specific heat of the mixture at constant volume is ……

n_1 mole of a monoatomic gas is mixed with n_2 mole of a diatomic gas. (Assume gases are ideal). If for the mixture adiabatic contant is found to be 1.5, then n_1 : n_2 is :

For one mole of a monoatomic gas match the following.

One mole of an ideal monoatomic gas is mixed with one mole of an ideal diatomic gas. The molar specific heat of the mixture at constant volume is (in Calories )