`sin 4530^o =`
1. `1/2`
2. `-1/2`
3. `sqrt 3/2`
4. `-sqrt 3/2`

The value of sin 60 is: A. sqrt 1//2 B. sqrt 3//2 C. 1//sqrt 2 D. sqrt""1//sqrt""2

Tangents drawn from (2, 0) to the circle x^2 + y^2 = 1 touch the circle at A and B . Then (A) A-= (1/2, sqrt(3)/2) , B -= (-1/2, - sqrt(3)/2) (B) A-= (- 1/2, (-sqrt(3)/2) , B -= (1/2, sqrt(3)/2) (C) A-= (1/2, sqrt(3)/2) , B-= (1/2, - sqrt(3)/2) (D) A-= (1/2, - sqrt(3)/2), B-= (1/2, sqrt(3)/2)

Cos(765^(@)) is ( 1 ) 1/2 ( 2 ) sqrt (2) ( 3 ) 1/sqrt(2) ( 4 ) 2 : sqrt(2)

Prove that sin ((23pi)/24) = sqrt((2 sqrt2 - sqrt3 -1)/(4 sqrt2))

2sin 60^(@)-cos180^(@)+(1//3)sin270^(@)= A) sqrt2+(3)/(2) B) sqrt3+(2)/(3) C) sqrt2-(3)/(2) D) sqrt3-(2)/(3)

Simplify (1/2+1/sqrt2-sqrt3)/(sqrt3-1/sqrt2-1/sqrt3)

Given b=2,c=sqrt(3),/_A=30^(0), then inradius of o+ABC is (sqrt(3)-1)/(2) (b) (sqrt(3)+1)/(2) (c) (sqrt(3)-1)/(4) (d) none of these

Find the principal of : (1) sin ^(-1)((1)/(2)) (2) tan^(-1)(-sqrt(3)) (3) cos^(-1)(-(1)/(sqrt(2))) (4) sin^(-1)(-(1)/(2)) .