If `A=[[4,3],[3,2]]` then `A^(-1)` is
a) `[[2,-3],[-3,4]]` b) `[[-2,3],[3,-4]]` C)`[[2,-3],[-4,3]]` D)`[[-2,4],[3,3]]`

Let A= [[2,4],[3,2]], B=[[1,3],[-2,5]], C=[[-2,5],[3,4]] find 3A-C

15. For matrix A=[(2,3),(-4,5)] , (adjA)^T is equal to (A) [(5,-3),(4,2)] (B) [(5,4),(-3,2)] (C) [(5,3),(4,-2)] (D) [(5,-3),(-4,2)]

The inverse of the matrix [(2,3),(-4,7)] is (A) [(-2,-3),(4,-7)] (B) 1/26 [(7,-3),(4,2)] (C) [(7,4),(-3,2)] (D) [(7,-3),(4,2)]

If a=2b, then a:b=2:1 (b) 1:2( c) 3:4 (d) 4:3

If x/2+1/3=1, then x= 3/4 (b) 4/3 -3/4 (d) (-4)/3

A=[[2,1],[4,1]]; B=[[3,4],[2,3]] & c=[[3,-4],[-2,3]], tr(A)+tr[(ABC)/2]+tr[ (A(BC)^2)/4]+tr[(A(BC)^2)/8]+.....oo is:

If (a)/(b)=(4)/(3), then (3a+2b)/(3a-2b)=?( a) -1 (b) 3 (c) 5(d)6