Successive IP of an element 'M' are 8.3, 25.1, 37.9, 259.3 and 340.1 eV. The formula of its bromide is

The first, second, third and fourth, ionization potential values of an element are 8.4, 25.15, 37.92 and 256.3eV respectively. The element is

The values of IE_(1),IE_(2),IE_(3),IE_(4) and IE_(5) of an element are 7.1, 14.3, 34.5, 46.8 and 162.2 eV respectively. The element is likely to be

The values of IE_1 , IE_2 , IE_3, IE_4 and IE_5 of an element are 5.98, 18.82, 28.44, 120 and 153.8 eV respectively. The element is likely to be

The formula of the sulphate of an element M is M_2(SO_4)_3 . Write the formula of its Chloride.

The formula of the sulphate of an element M is M_2(SO_4)_3 . Write the formula of its Oxide.

Value of IE_(1), IE_(2), IE_(3) of an element are 9.3, 18.2 and 553.8 eV . Predict group number in Modern Periodic Table.

The IP_(1),IP_(2),IP_(3),IP_(4) and IP_(5) of an element are 7.1, 14.3, 34.5, 46.8, 162.2V respectively. The element is likely to be -

The formula of the sulphate of an element M is M_2(SO_4)_3 . Write the formula of its Phosphate.

The formula of the sulphate of an element M is M_2(SO_4)_3 . Write the formula of its Acetate.

The first, second and third ionization energies (E_(1),E_(2)&E_(3)) for an element are 7eV, 12.5 eV and 42.5 eV respectively. The most stable oxidation state of the element will be: