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Points (6,8),(3,7),(-2,-2) and (1,-1) ar...

Points (6,8),(3,7),(-2,-2) and (1,-1) are joined to form a quadrilateral. What will be the structure of the quadrilateral?

A

Rhombus

B

Parallelogram

C

Square

D

Rectangle

Text Solution

AI Generated Solution

The correct Answer is:
To determine the structure of the quadrilateral formed by the points (6,8), (3,7), (-2,-2), and (1,-1), we will follow these steps: ### Step 1: Assign Points Let's label the points: - A(6, 8) - B(3, 7) - C(-2, -2) - D(1, -1) ### Step 2: Calculate the Slopes We will calculate the slopes of the sides AB, CD, AD, and BC using the slope formula: \[ \text{slope} = \frac{y_2 - y_1}{x_2 - x_1} \] #### Slope of AB Using points A(6, 8) and B(3, 7): \[ \text{slope of AB} = \frac{7 - 8}{3 - 6} = \frac{-1}{-3} = \frac{1}{3} \] #### Slope of CD Using points C(-2, -2) and D(1, -1): \[ \text{slope of CD} = \frac{-1 - (-2)}{1 - (-2)} = \frac{1}{3} \] #### Slope of AD Using points A(6, 8) and D(1, -1): \[ \text{slope of AD} = \frac{-1 - 8}{1 - 6} = \frac{-9}{-5} = \frac{9}{5} \] #### Slope of BC Using points B(3, 7) and C(-2, -2): \[ \text{slope of BC} = \frac{-2 - 7}{-2 - 3} = \frac{-9}{-5} = \frac{9}{5} \] ### Step 3: Analyze the Slopes - The slopes of AB and CD are equal: \(\frac{1}{3}\), indicating that lines AB and CD are parallel. - The slopes of AD and BC are equal: \(\frac{9}{5}\), indicating that lines AD and BC are also parallel. ### Step 4: Determine the Structure Since both pairs of opposite sides are parallel, we can conclude that the quadrilateral is a **parallelogram**. ### Step 5: Check for Special Types To determine if it is a rectangle, rhombus, or square, we need to check the lengths of the sides and the angles. #### Length of AB Using the distance formula: \[ AB = \sqrt{(6-3)^2 + (8-7)^2} = \sqrt{3^2 + 1^2} = \sqrt{9 + 1} = \sqrt{10} \] #### Length of CD Using the distance formula: \[ CD = \sqrt{(1 - (-2))^2 + (-1 - (-2))^2} = \sqrt{(1 + 2)^2 + (-1 + 2)^2} = \sqrt{3^2 + 1^2} = \sqrt{9 + 1} = \sqrt{10} \] #### Length of AD Using the distance formula: \[ AD = \sqrt{(6-1)^2 + (8-(-1))^2} = \sqrt{5^2 + 9^2} = \sqrt{25 + 81} = \sqrt{106} \] #### Length of BC Using the distance formula: \[ BC = \sqrt{(3 - (-2))^2 + (7 - (-2))^2} = \sqrt{(3 + 2)^2 + (7 + 2)^2} = \sqrt{5^2 + 9^2} = \sqrt{25 + 81} = \sqrt{106} \] ### Conclusion Since the opposite sides are equal and parallel, but the lengths of adjacent sides are not equal, the quadrilateral is a **parallelogram** but not a rectangle, rhombus, or square. ---
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