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An adult and a minor boy, standing on th...

An adult and a minor boy, standing on the ground, are 4 metres apart. The height of the adult is 4 times the height of the minor boy. If at the mid-point of the line segment joining their feet, the angles of elevation of their tops are complementary, then the height of the minor boy is

A

1.3 m

B

1.5 m

C

1 m

D

1.2 m

Text Solution

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The correct Answer is:
To solve the problem step-by-step, we will denote the height of the minor boy as \( h \). Consequently, the height of the adult will be \( 4h \). ### Step 1: Understand the setup The adult and the minor boy are standing 4 meters apart. The midpoint between them is 2 meters from each of them. ### Step 2: Define the angles of elevation Let \( x \) be the angle of elevation from the midpoint to the top of the adult, and \( y \) be the angle of elevation to the top of the minor boy. Since the angles are complementary, we have: \[ x + y = 90^\circ \] ### Step 3: Set up the triangles From the midpoint (M), we can form two right triangles: 1. Triangle ABM (where A is the top of the adult, B is the foot of the adult, and M is the midpoint) 2. Triangle CDM (where C is the top of the minor boy, D is the foot of the minor boy, and M is the midpoint) ### Step 4: Write the tangent equations For triangle ABM: \[ \tan(x) = \frac{\text{height of adult}}{\text{base}} = \frac{4h}{2} = 2h \] Thus, we have: \[ \tan(x) = 2h \quad \text{(Equation 1)} \] For triangle CDM: \[ \tan(y) = \frac{\text{height of minor boy}}{\text{base}} = \frac{h}{2} \] Thus, we have: \[ \tan(y) = \frac{h}{2} \quad \text{(Equation 2)} \] ### Step 5: Use the complementary angle identity Since \( x + y = 90^\circ \), we can use the identity: \[ \tan(x + y) = \tan(90^\circ) \rightarrow \text{undefined (infinity)} \] This leads us to: \[ 1 - \tan(x) \tan(y) = 0 \] Substituting the values from Equation 1 and Equation 2: \[ 1 - (2h) \left(\frac{h}{2}\right) = 0 \] ### Step 6: Solve for \( h \) Simplifying the equation: \[ 1 - h^2 = 0 \] This implies: \[ h^2 = 1 \] Taking the square root: \[ h = 1 \text{ meter} \] ### Conclusion The height of the minor boy is \( 1 \) meter. ---
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