In the figure, ABDCA represents a quadra...

In the figure, ABDCA represents a quadrant of a circle of radius 7 cm with centre A. Find the area of the shaded portion.

A

`14 cm^(2)`

B

`24.5 cm^(2)`

C

`38.5 cm^(2)`

D

`31.5 cm^(2)`

Verified by Experts

The correct Answer is:

D

AREAS RELATED TO CIRCLES
SCIENCE OLYMPIAD FOUNDATION |Exercise Everyday Mathematics |5 Videos
AREAS RELATED TO CIRCLES
SCIENCE OLYMPIAD FOUNDATION |Exercise Achievers Section (HOTS)|5 Videos
ARITHMETIC PROGRESSIONS
SCIENCE OLYMPIAD FOUNDATION |Exercise ACHIEVERS SECTION (HOTS)|5 Videos

Similar Questions

Explore conceptually related problems

In Fig.15.35, AOBCA represents a quadrant of a circle of radius 3.5cm with centre O. Calculate the area of the shaded portion (Take pi=22/7) .

In the figure given below, ABCO represents a quadrant of a circle of radius 10.5 cm with centre O. Calculate the area of shaded portion, if OD = DC.

In the figure, the area of the shaded portion is :

AOBC is a quadrant of a circle of radius 10 cm. Calculate the area of the shaded portion. (Use pi = 3.14 )

The radius of each circle is 'a'. Then the area of the shaded portion is :

In the given figure, OABC is a square of side 7cm. If COPB is a quadrant of a circle with centre C find the area of the shaded region.

ABCP is a quadrant of a circle of radius 14 cm. with AC as diameter, a semicircle is drawn. Find the area of the shaded portion

In Fig. 19.60, A B C is an equilateral triangle inscribed in a circle of radius 4 cm with centre O . Find the area of the shaded region. (FIGURE)

In figure, OACB is a quadrant of a circle with centre O and radius 7 cm. If AD = 2 cm, find the area of the shaded region.

BCP is a quadrant of a circle of radius 14cm. With AC as diameter,a semi-circle is drawn. Find the area of the shaded portion.