An organic compound `X` has a melting point of `-33^@C` and a boiling point of `66^@C`. Which of the following is true about this substance ?

Options

A. At `-100^@C`, `X` exists in solid state
B. At `0^@C`, `X` exists in liquid state
C. At `90^@C`, `X` exists in gaseous state
D. All of these

Explanation

To analyze the organic compound `X` with a melting point of `-33°C` and a boiling point of `66°C`, we can follow these steps:

### Step 1: Understand the Melting and Boiling Points
- The melting point of a substance is the temperature at which it changes from solid to liquid. For compound `X`, this occurs at `-33°C`.
- The boiling point is the temperature at which it changes from liquid to gas. For compound `X`, this occurs at `66°C`.

### Step 2: Determine the State of Matter at Different Temperatures
- At temperatures below `-33°C`, compound `X` will be in a solid state.
- At temperatures between `-33°C` and `66°C`, compound `X` will be in a liquid state.
- At temperatures above `66°C`, compound `X` will be in a gaseous state.

### Step 3: Analyze the Implications
- Since the melting point is significantly lower than room temperature (around `20-25°C`), it indicates that at room temperature, compound `X` will be in a liquid state.
- The boiling point being higher than room temperature suggests that it will not vaporize at normal conditions.

### Conclusion
Based on the melting and boiling points, we can conclude that:
- The organic compound `X` is a liquid at room temperature.