An element `P` forms an oxide with formula `PO`. The formulae of its sulphate and phosphate will be respectively

Options

A. `PSO and P_(2)(PO_4)_3`
B. `P_(2)(SO_4)_3 and PPO_4`
C. `P(SO_4)_2 and P(PO_4)_2`
D. `PSO_4 and P_(3)(PO_4)_2`

Explanation

To find the formulae of the sulphate and phosphate of the element P, which forms an oxide with the formula PO, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Oxidation State of Element P:**
- The oxide formula is PO, which suggests that the oxidation state of P is +2 (since O has an oxidation state of -2).
- Therefore, we can conclude that P has an oxidation state of +2.

2. **Determine the Formula of Sulphate:**
- The sulphate ion has the formula SO₄²⁻.
- To form a compound with sulphate, we need to balance the charges. Since P has an oxidation state of +2, we can combine it with the sulphate ion:
- The formula will be PSO₄, as the +2 charge from P balances the -2 charge from SO₄²⁻.

3. **Determine the Formula of Phosphate:**
- The phosphate ion has the formula PO₄³⁻.
- To balance the charges with P, which has a +2 oxidation state, we need to find the appropriate ratio:
- Since the phosphate ion has a -3 charge, we need 3 P atoms to balance the charge of 2 from each P atom.
- Therefore, the formula will be P₃(PO₄)₂, which indicates that we need 2 phosphate ions to balance the charges.

4. **Final Formulas:**
- The formula for the sulphate of element P is PSO₄.
- The formula for the phosphate of element P is P₃(PO₄)₂.

### Summary of Answers:
- The formula of the sulphate is **PSO₄**.
- The formula of the phosphate is **P₃(PO₄)₂**.