The maximum amount of sodium that can be obtained by electrolysis of 117 g of sodium chloride is
[Atomic mass of Na = 23 u, Cl = 35.5 u]

Options

A. 40 g
B. 46 g
C. 52 g
D. 23 g

Explanation

To find the maximum amount of sodium that can be obtained by the electrolysis of 117 g of sodium chloride (NaCl), we can follow these steps:

### Step 1: Calculate the molar mass of sodium chloride (NaCl).
The molar mass of NaCl can be calculated by adding the atomic masses of sodium (Na) and chlorine (Cl).

- Atomic mass of Na = 23 u
- Atomic mass of Cl = 35.5 u

**Molar mass of NaCl = Atomic mass of Na + Atomic mass of Cl**
= 23 u + 35.5 u
= 58.5 u

### Step 2: Calculate the number of moles of sodium chloride in 117 g.
To find the number of moles of NaCl, we use the formula:

**Number of moles = Mass (g) / Molar mass (g/mol)**

Substituting the values we have:

**Number of moles of NaCl = 117 g / 58.5 g/mol**
= 2 moles of NaCl

### Step 3: Determine the amount of sodium produced from the moles of sodium chloride.
From the electrolysis of sodium chloride, we know that 1 mole of NaCl produces 1 mole of sodium (Na). Therefore, the number of moles of sodium produced will be equal to the number of moles of NaCl.

**Moles of Na produced = Moles of NaCl = 2 moles**

### Step 4: Calculate the mass of sodium produced.
To find the mass of sodium produced, we multiply the number of moles of sodium by its molar mass.

**Mass of Na = Number of moles × Molar mass of Na**
= 2 moles × 23 g/mol
= 46 g

### Final Answer:
The maximum amount of sodium that can be obtained by the electrolysis of 117 g of sodium chloride is **46 g**.

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