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The ratio of molecules present in 6.6 g ...

The ratio of molecules present in 6.6 g of `CO_2` and 3.2 g of `SO_2` is:

A

`4:1`

B

`1:4`

C

`3:1`

D

`1:3`

Text Solution

Verified by Experts

The correct Answer is:
C
Molecular mass of `CO_2 = 44 u`
Molar mass of `CO_2 = 44 g`
No. of molecules of `CO_2` present in 6.6g of `CO_2`
`= (6.6)/(44) xx 6.023 xx 10^(23) = 9.034 xx 10^(22)`
No. of molecules of `SO_2` present in 3.2 g of `SO_2`
`= (3.2)/(64) xx 6.023 xx 10^(23) = 3.0111 xx 10^(22)`
Ratio of molecules of `CO_2 and SO_2`
`= (9.033 xx 10^(22))/(3.011 xx 10^(22)) = 3` , i.e., 3:1
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