Home
Class 9
CHEMISTRY
The graphical representation of number o...

The graphical representation of number of molecules of different gases is given. Which gases are placed at correct position?

A

`H_2, He`

B

`N_2, CH_4`

C

`He , CH_4 `

D

`H_2, CH_4`

Text Solution

Verified by Experts

The correct Answer is:
C

2g of `H_2 -= 6.023 xx 10^(23)` molecules
1 g of `H_2 -= (6.023 xx 10^(23))/(2)` molecules
1 g of `H_2 -= (6.023 xx 10^(23))/(2)` molecules i.e., `3.011 xx 10^(23)` molecules
4 g of `He -= 6.023 xx 10^(23)` molecules
2g of `He -= (6.023 xx 10^(23))/(4) xx 2` molecules i.e., `3.011 xx 10^(23)` molecules
28 g of `N_2 -= 6.023 xx 10^(23)` molecules
3g of `N_2 -= (6.023 xx 10^(23))/(28) xx 3 ` molecules i.e., `0.6453 xx 10^(23)` molecules
16 g of `CH_4 -= 6.023 xx 10^(23)` molecules
4g of `CH_4 -= (6.023 xx 10^(23))/(16) xx 4 ` molecules i.e., ` 1.505 xx 10^(23)` molecules
Thus , in graph , He and `CH_4 ` gases are placed at correct position
Promotional Banner

Topper's Solved these Questions

  • ATOMS AND MOLECULES

    SCIENCE OLYMPIAD FOUNDATION |Exercise ACHIEVERS SECTION (HOTS)|5 Videos
  • CLASS 9 SAMPLE PAPER FINAL 4

    SCIENCE OLYMPIAD FOUNDATION |Exercise SCIENCE|8 Videos

Similar Questions

Explore conceptually related problems

Select the correct graphical representation :

Diagrammatic representation of Miller's experiment is given below. Identify the gases marked A and B:

Identify the number of noble gases.

The ratio of diameters of molecules of the two gases is 3:5 and their mean free path of the molecule is in the ratio of 5:3 then the ratio of number density of the two gases is

Which is not the graphical representation for the zeroth order reaction ?