In a monohybrid cross between two heterozygous individuals, percentage of heterozygous individuals obtained in `F_(1)` generation is

Options

A. `25%`
B. `50%`
C. `75%`
D. `100%`

Explanation

To solve the question regarding the percentage of heterozygous individuals obtained in the F1 generation from a monohybrid cross between two heterozygous individuals, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Parents**:
In a monohybrid cross, we are dealing with two heterozygous individuals. Let's denote the alleles as follows:
- Parent 1: Tt (heterozygous)
- Parent 2: Tt (heterozygous)

2. **Determine the Gametes**:
Each parent can produce two types of gametes due to their heterozygous nature:
- Parent 1 can produce gametes: T and t
- Parent 2 can produce gametes: T and t

3. **Set Up the Punnett Square**:
We can set up a Punnett square to visualize the potential offspring from these gametes:
```
T t
----------------
T | TT | Tt |
----------------
t | Tt | tt |
----------------
```

4. **Analyze the Offspring**:
From the Punnett square, we can see the following genotypes of the offspring:
- TT (homozygous dominant): 1
- Tt (heterozygous): 2
- tt (homozygous recessive): 1

5. **Calculate the Percentage of Heterozygous Individuals**:
To find the percentage of heterozygous individuals (Tt) in the F1 generation:
- Total offspring = 4 (1 TT + 2 Tt + 1 tt)
- Heterozygous offspring (Tt) = 2
- Percentage of heterozygous individuals = (Number of Tt / Total Offspring) × 100
- Percentage of heterozygous individuals = (2 / 4) × 100 = 50%

### Conclusion:
The percentage of heterozygous individuals obtained in the F1 generation from a monohybrid cross between two heterozygous individuals is **50%**.