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An object moving at a constant speed of ...

An object moving at a constant speed of 4 m/s towards a convex mirror of focal length 1 m is at a distance of 19 m. The average speed of the image is

A

`(1)/(20)` m/s

B

`(1)/(80)` m/s

C

20 m/s

D

80 m/s

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The correct Answer is:
To find the average speed of the image formed by a convex mirror when an object is moving towards it, we can follow these steps: ### Step 1: Understand the Given Information - The object is moving towards a convex mirror with a constant speed of \(4 \, \text{m/s}\). - The focal length \(f\) of the convex mirror is \(1 \, \text{m}\). - The initial distance of the object from the mirror \(u\) is \(19 \, \text{m}\) (we will take it as negative in the mirror formula). ### Step 2: Use the Mirror Formula The mirror formula is given by: \[ \frac{1}{f} = \frac{1}{v} + \frac{1}{u} \] Where: - \(f\) = focal length of the mirror (positive for convex mirrors) - \(v\) = image distance (to be determined) - \(u\) = object distance (negative for real objects) ### Step 3: Calculate Initial Image Distance \(v_1\) Substituting the values into the mirror formula: \[ \frac{1}{1} = \frac{1}{v_1} + \frac{1}{-19} \] This simplifies to: \[ 1 = \frac{1}{v_1} - \frac{1}{19} \] Rearranging gives: \[ \frac{1}{v_1} = 1 + \frac{1}{19} = \frac{19 + 1}{19} = \frac{20}{19} \] Thus, \[ v_1 = \frac{19}{20} \, \text{m} \] ### Step 4: Calculate Object Distance After 1 Second After 1 second, the object moves towards the mirror: \[ u = - (19 - 4 \times 1) = -15 \, \text{m} \] ### Step 5: Calculate New Image Distance \(v_2\) Using the mirror formula again with the new object distance: \[ \frac{1}{1} = \frac{1}{v_2} + \frac{1}{-15} \] This simplifies to: \[ 1 = \frac{1}{v_2} - \frac{1}{15} \] Rearranging gives: \[ \frac{1}{v_2} = 1 + \frac{1}{15} = \frac{15 + 1}{15} = \frac{16}{15} \] Thus, \[ v_2 = \frac{15}{16} \, \text{m} \] ### Step 6: Calculate the Average Speed of the Image The average speed of the image can be calculated using the change in image distance over the time interval: \[ \text{Average Speed} = \frac{v_2 - v_1}{\Delta t} \] Where \(\Delta t = 1 \, \text{s}\): \[ \text{Average Speed} = \frac{\frac{15}{16} - \frac{19}{20}}{1} \] ### Step 7: Find a Common Denominator To subtract the fractions, find a common denominator (which is 80): \[ \frac{15}{16} = \frac{75}{80}, \quad \frac{19}{20} = \frac{76}{80} \] Thus, \[ \text{Average Speed} = \frac{75/80 - 76/80}{1} = \frac{-1}{80} \, \text{m/s} \] ### Final Answer The average speed of the image is: \[ \text{Average Speed} = \frac{1}{80} \, \text{m/s} \]

To find the average speed of the image formed by a convex mirror when an object is moving towards it, we can follow these steps: ### Step 1: Understand the Given Information - The object is moving towards a convex mirror with a constant speed of \(4 \, \text{m/s}\). - The focal length \(f\) of the convex mirror is \(1 \, \text{m}\). - The initial distance of the object from the mirror \(u\) is \(19 \, \text{m}\) (we will take it as negative in the mirror formula). ### Step 2: Use the Mirror Formula ...
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