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Three different containers contain diffe...

Three different containers contain different quantities of mixtures of milk and wate r, whose measurements are 403 L, 434 L and 465 L. What biggest measure must be there to measure all the different quantities exactly?

A

1 L

B

7 L

C

31 L

D

41 L

Text Solution

AI Generated Solution

The correct Answer is:
To find the biggest measure that can be used to measure the quantities of 403 L, 434 L, and 465 L exactly, we need to determine the greatest common divisor (GCD) or highest common factor (HCF) of these three numbers. Here’s how we can do that step by step: ### Step 1: Prime Factorization of Each Number 1. **Prime Factorization of 403**: - 403 is not divisible by 2 (since it's odd). - Check divisibility by 3: \(4 + 0 + 3 = 7\) (not divisible by 3). - Check divisibility by 5 (last digit is not 0 or 5). - Check divisibility by 7: \(403 ÷ 7 \approx 57.57\) (not divisible). - Check divisibility by 11: \(403 ÷ 11 \approx 36.64\) (not divisible). - Check divisibility by 13: \(403 ÷ 13 \approx 31\) (not divisible). - Check divisibility by 17: \(403 ÷ 17 \approx 23.59\) (not divisible). - Check divisibility by 19: \(403 ÷ 19 \approx 21.21\) (not divisible). - Finally, check divisibility by 31: \(403 ÷ 31 = 13\) (exact). - Thus, \(403 = 31 \times 13\). 2. **Prime Factorization of 434**: - 434 is even, so divide by 2: \(434 ÷ 2 = 217\). - Now factor 217: Check divisibility by 3 (not divisible). - Check divisibility by 7: \(217 ÷ 7 \approx 31\) (exact). - Thus, \(434 = 2 \times 7 \times 31\). 3. **Prime Factorization of 465**: - 465 is odd, check divisibility by 3: \(465 ÷ 3 = 155\). - Now factor 155: Check divisibility by 5: \(155 ÷ 5 = 31\). - Thus, \(465 = 3 \times 5 \times 31\). ### Step 2: List the Prime Factors - **403**: \(31 \times 13\) - **434**: \(2 \times 7 \times 31\) - **465**: \(3 \times 5 \times 31\) ### Step 3: Identify Common Factors The common prime factor among all three numbers is **31**. ### Step 4: Conclusion The greatest common divisor (GCD) or highest common factor (HCF) of 403, 434, and 465 is **31**. Therefore, the biggest measure that can be used to measure all three quantities exactly is **31 L**.
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