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A man walks 6 km to the East and then tu...

A man walks 6 km to the East and then turns to the South and walks 5 km. Again he turns to the East and walks 6 km. Next, he turns northwards and walks 10 km. How far is he now from his starting point ?

A

5 km

B

12 km

C

13 km

D

17 km

Text Solution

Verified by Experts

The correct Answer is:
C

AF = AB + CD = 6 + 6 = 12 km
Also, EF = ED - BC = 10 - 5 = 5 km
By using pythagoras theorem,
`AE^(2) = AF^(2) + EF^(2) = 12^(2) + 5^(2) = 144 + 25 = 169`
`rArr AE = 13 km`
`therefore` The man is 13 km far from the starting point.
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