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To write a letter with a graphite pencil...

To write a letter with a graphite pencil, 0.001 g of carbon is required. Number of moles of carbon atoms and the total number of carbon atoms used in writing the letter are respectively.

A

`3.02 xx 10^(23) and 6.023 xx 10^(23)`

B

`1 and 3.02 xx 10^(24)`

C

`8.33 xx 10^(-5) and 5.02 xx 10^(19)`

D

`5.02 xx 10^(19) and 3.02 xx 10^(24)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to calculate the number of moles of carbon atoms and the total number of carbon atoms in 0.001 g of carbon. ### Step-by-Step Solution: 1. **Identify the mass of carbon**: The mass of carbon used to write the letter is given as 0.001 g. 2. **Determine the molar mass of carbon**: The molar mass of carbon (C) is approximately 12 g/mol. 3. **Calculate the number of moles of carbon**: The number of moles (n) can be calculated using the formula: \[ n = \frac{\text{mass (g)}}{\text{molar mass (g/mol)}} \] Substituting the values: \[ n = \frac{0.001 \text{ g}}{12 \text{ g/mol}} = 8.33 \times 10^{-5} \text{ moles} \] 4. **Calculate the total number of carbon atoms**: To find the total number of atoms, we use Avogadro's number, which is approximately \(6.022 \times 10^{23} \text{ atoms/mol}\). The total number of atoms can be calculated as: \[ \text{Total atoms} = n \times \text{Avogadro's number} \] Substituting the values: \[ \text{Total atoms} = 8.33 \times 10^{-5} \text{ moles} \times 6.022 \times 10^{23} \text{ atoms/mol} \] Performing the multiplication: \[ \text{Total atoms} \approx 5.01 \times 10^{19} \text{ atoms} \] ### Final Answer: The number of moles of carbon atoms is approximately \(8.33 \times 10^{-5}\) moles, and the total number of carbon atoms used in writing the letter is approximately \(5.01 \times 10^{19}\) atoms. ---
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