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An experimental spacecraft is found to h...

An experimental spacecraft is found to have weight W when assembled before launching from a rocket site. It is placed in a circular orbit at a height h = 6R above the surface of the earth (of radius R). The gravitational force acting on the spacecraft in this orbit is ________.

A

W/6

B

W/7

C

W/36

D

W/49

Text Solution

AI Generated Solution

The correct Answer is:
To find the gravitational force acting on the spacecraft in a circular orbit at a height \( h = 6R \) above the surface of the Earth, we can follow these steps: ### Step 1: Understand the Weight on the Surface When the spacecraft is on the surface of the Earth, its weight \( W \) is given by the formula: \[ W = mg \] where \( m \) is the mass of the spacecraft and \( g \) is the acceleration due to gravity at the Earth's surface. ### Step 2: Determine the Height Above the Earth's Surface The spacecraft is in a circular orbit at a height \( h = 6R \) above the surface of the Earth. The radius of the Earth is \( R \), so the total distance from the center of the Earth to the spacecraft in orbit is: \[ d = R + h = R + 6R = 7R \] ### Step 3: Calculate the Gravitational Acceleration at Height \( h \) The gravitational acceleration \( g' \) at a distance \( d \) from the center of the Earth is given by: \[ g' = \frac{GM}{d^2} \] where \( G \) is the universal gravitational constant and \( M \) is the mass of the Earth. Substituting \( d = 7R \): \[ g' = \frac{GM}{(7R)^2} = \frac{GM}{49R^2} = \frac{g}{49} \] Here, \( g \) is the acceleration due to gravity at the Earth's surface. ### Step 4: Calculate the Weight in Orbit Now, the weight of the spacecraft in orbit \( W' \) can be calculated using the new gravitational acceleration \( g' \): \[ W' = mg' = m \left(\frac{g}{49}\right) = \frac{mg}{49} = \frac{W}{49} \] where we have replaced \( mg \) with \( W \) since \( W \) is the weight of the spacecraft at the Earth's surface. ### Conclusion Thus, the gravitational force acting on the spacecraft in this orbit is: \[ W' = \frac{W}{49} \] ### Final Answer The gravitational force acting on the spacecraft in this orbit is \( \frac{W}{49} \). ---
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