Two compounds X and Y have the same molecular formula, `C_(3)H_(6)O_(2)`. Identify the functional groups and structural formulae of X and Y.

Options

A. `-COOH and - COOR,X = CH_(3)CH_(2)COOH,Y= CH_(3)COOCH_(3)`
B. `CHO and - CO,X= CH_(3)CH_(2)CHO,Y = CH_(3)CH_(2)CHO`
C. `-CO and - COOH, X = CH_(3) COCH_(3),Y = CH_(3)CH_(2)COOH`
D. `-CHO and - COOH,X = CH_(3)CH_(2)OCH_(3), Y = CH_(3)CH_(2)COOH`

Answer

To solve the problem of identifying the functional groups and structural formulae of the two compounds X and Y with the molecular formula \( C_3H_6O_2 \), we can follow these steps:

### Step 1: Analyze the Molecular Formula
The given molecular formula is \( C_3H_6O_2 \). This indicates that the compound contains 3 carbon atoms, 6 hydrogen atoms, and 2 oxygen atoms.

**Hint:** Look for common functional groups that can be formed with 3 carbons and 2 oxygens.

### Step 2: Identify Possible Functional Groups
The presence of two oxygen atoms suggests that the compounds could either be a carboxylic acid or an ester.

1. **Carboxylic Acid:** The general formula for a carboxylic acid is \( RCOOH \).
2. **Ester:** The general formula for an ester is \( RCOOR' \).

**Hint:** Think about how the functional groups can be arranged with the given number of carbons and oxygens.

### Step 3: Construct Structural Formula for Compound X
Let's assume Compound X is a carboxylic acid. We can represent it as follows:

- For a carboxylic acid, we can have:
- \( CH_3CH_2COOH \) (Propanoic acid)

This has the structure:
```
O
||
CH3-CH2-C-OH
```

**Hint:** Ensure that the structure adheres to the molecular formula \( C_3H_6O_2 \).

### Step 4: Construct Structural Formula for Compound Y
Now, let's assume Compound Y is an ester. We can represent it as follows:

- For an ester, we can have:
- \( CH_3COOCH_3 \) (Methyl acetate)

This has the structure:
```
O
||
CH3-C-O-CH3
```

**Hint:** Check that the ester also fits the molecular formula \( C_3H_6O_2 \).

### Step 5: Summarize the Findings
- **Compound X (Carboxylic Acid):** Propanoic acid with the structure \( CH_3CH_2COOH \).
- **Compound Y (Ester):** Methyl acetate with the structure \( CH_3COOCH_3 \).

### Conclusion
The two compounds with the molecular formula \( C_3H_6O_2 \) are:
- **X:** Propanoic acid (Functional group: Carboxylic acid)
- **Y:** Methyl acetate (Functional group: Ester)