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When a heater wire is connected to a 230...

When a heater wire is connected to a 230 V main supply power dissipation is `P_(1)`. Now the same wire is cut into three equal pieces and are connected in parallel to the same source, power dissipation in this case is `P_(2)`. The ratio `P_(2)`, `P_(1)`, is

A

`1:3`

B

`3:1`

C

`9:1`

D

`1:9`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to determine the ratio of power dissipation when a heater wire is connected to a voltage supply in two different configurations: first as a whole wire and then as three equal pieces connected in parallel. ### Step-by-Step Solution: 1. **Identify the Power Dissipation in the First Case (P1)**: - When the heater wire of resistance \( R \) is connected to a voltage supply \( V \), the power dissipation \( P_1 \) can be calculated using the formula: \[ P_1 = \frac{V^2}{R} \] - Here, \( V = 230 \, \text{V} \). 2. **Determine the Resistance of Each Piece After Cutting**: - When the wire is cut into three equal pieces, the length of each piece becomes \( \frac{L}{3} \). - The resistance of one piece \( R_1 \) can be calculated as: \[ R_1 = \frac{R}{3} \] 3. **Calculate the Equivalent Resistance When Connected in Parallel**: - When three resistances \( R_1 \) are connected in parallel, the equivalent resistance \( R_{eq} \) is given by: \[ \frac{1}{R_{eq}} = \frac{1}{R_1} + \frac{1}{R_1} + \frac{1}{R_1} = \frac{3}{R_1} \] - Substituting \( R_1 = \frac{R}{3} \): \[ \frac{1}{R_{eq}} = \frac{3}{\frac{R}{3}} = \frac{9}{R} \implies R_{eq} = \frac{R}{9} \] 4. **Identify the Power Dissipation in the Second Case (P2)**: - The power dissipation \( P_2 \) when the three pieces are connected in parallel can be calculated using: \[ P_2 = \frac{V^2}{R_{eq}} = \frac{V^2}{\frac{R}{9}} = \frac{9V^2}{R} \] 5. **Calculate the Ratio of Power Dissipation (P2/P1)**: - Now, we can find the ratio of \( P_2 \) to \( P_1 \): \[ \frac{P_2}{P_1} = \frac{\frac{9V^2}{R}}{\frac{V^2}{R}} = \frac{9V^2}{R} \cdot \frac{R}{V^2} = 9 \] 6. **Final Result**: - Therefore, the ratio \( \frac{P_2}{P_1} \) is: \[ \frac{P_2}{P_1} = 9 \] ### Conclusion: The ratio \( P_2 : P_1 \) is \( 9 : 1 \).
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