Study the given reaction carefully.
`CuO + H_(2) to Cu + H_(2)O`
Which of the following statements is incorrect regarding this reaction?

Options

A. The reaction is a redox reaction.
B. `CuO` is the oxidising agent.
C. `H_(2)` is getting reduced.
D. `H_(2)` is the reducing agent.

Answer

To determine which statement is incorrect regarding the reaction `CuO + H₂ → Cu + H₂O`, we need to analyze the reaction step by step.

### Step 1: Identify the Reactants and Products
The reactants in this reaction are Copper(II) oxide (CuO) and Hydrogen gas (H₂). The products are Copper (Cu) and Water (H₂O).

### Step 2: Determine Oxidation States
- In CuO, the oxidation state of Cu is +2 and O is -2.
- In H₂, the oxidation state of H is 0.
- In Cu, the oxidation state of Cu is 0.
- In H₂O, the oxidation state of H is +1 and O is -2.

### Step 3: Analyze Changes in Oxidation States
- CuO (Cu +2) is reduced to Cu (Cu 0), indicating that CuO is undergoing reduction (gaining electrons).
- H₂ (H 0) is oxidized to H₂O (H +1), indicating that H₂ is undergoing oxidation (losing electrons).

### Step 4: Identify Oxidizing and Reducing Agents
- The substance that gets reduced (CuO) is the oxidizing agent.
- The substance that gets oxidized (H₂) is the reducing agent.

### Step 5: Classify the Reaction
Since there is both oxidation and reduction occurring in this reaction, it is classified as a redox reaction.

### Step 6: Evaluate the Statements
Now, we can evaluate the statements regarding the reaction:
1. CuO is the oxidizing agent. (True)
2. H₂ is the reducing agent. (True)
3. H₂ is getting oxidized. (False, because H₂ is the reducing agent and is being oxidized)
4. This is a redox reaction. (True)

### Conclusion
The incorrect statement regarding this reaction is: **H₂ is getting oxidized.**