`int (1-c^2)/(c(1-2c)) dx =`

Column I, a) int(e^(2x)-1)/(e^(2x)+1)dx is equal to b) int1/((e^x+e^(-x))^2)dx is equal to c) int(e^(-x))/(1+e^x)dx is equal to d) int1/(sqrt(1-e^(2x)))dx is equal to COLUMN II p) x-log[1+sqrt(1-e^(2x)]+c q) log(e^x+1)-x-e^(-x)+c r) log(e^(2x)+1)-x+c s) -1/(2(e^(2x)+1))+c

int(cos2x-1)/(cos2x+1)\ dx= (a) tanx-x+C (b) x+tanx+C (c) x-tanx+C (d) x-cotx+C

int e^x ((1-sinx)/(1-cosx)) dx= (A) e^xtan(x/2)+C (B) e^xcot(x/2)+C (C) -1/2 e^xtan(x/2)+C (D) -1/2 e^xcot(x/2)+C

int (dx)/((x+1)(x-2))=A log (x+1)+B log (x-2)+C , where

int(2^x)/(sqrt(1-4^x))dx=ksin^(- 1)2^x+c , then k =

Evaluate: (i) int(sin^2x)/(1+cosx)\ dx (ii) int(sec^2x+cos e c^2x)\ dx

Evaluate: (i) int1/(xlogxlog(logx)\ dx (ii) int(cos e c^2x)/(1+cotx)\ dx

Evaluate: int(cos e c^2x)/(1+cotx)dx

(1)/(c )int_(ac)^(bc)f((x)/(c ))dx=

Statement I int((1)/(1+x^(4)))dx=tan^(-1)(x^(2))+C Statement II int(1)/(1+x^(2))dx=tan^(-1)x +C