`2x+3y=5,3x-2y=1`

The equation 2x+y=5, x+3y =5, x-2y=0 have :

x+5y=15;2x-3y=1

2x+3y=3 4x+5y=3

Let A(2,-3) and B(-2,1) be vertices of a triangle ABC. If the centroid of this triangle moves on the line 2x+3y=1, then the locus of the vertex C is the line 2x+3y=92x-3y=73x+2y=53x-2y=3

Solve for (x,y) : 2x-3y =5 , 3x+4y = -1 .

STATEMENT-1: The straight lines 2x+3y+5=0and 3x-2y+1=0 are perpendicular to each other. STATEMENT-2: Two lines y=m_(1)x+c_(1)and y=m_(2)x+c_(2) where m_(1),m_(2)in R are perpendicular if m_(1),m_(2)=-1. STATEMENT-2: Two lines y=m_(1)xx+x_(1)and y=m_(2)x+c_(2)where m_(1),m_(2)inR are peprendicular if m_(1)m_(2)=-1.

Solve for x and y 2/(3x+2y)+3/(3x-2y)=17/5,5/(3x+2y)+1/(3x+2y)=6/5

Solve the following system of equations by matrix method : 5x+7y+2=0 4x+6y+3=0 5x+2y=3 3x+2y=5 3x+4y-5=0 x-y+3=0 3x+y=19 3x-y=23 3x+7y=4 x+2y=-1 3x+y=7 5x+3y=12