`3x+2y-4=0` and `2x-3y-7=0`

Solve the following system of linear equation graphically and shade the region between the two lines and x -axis.3x+2y-4=0,2x-3y-7=0

Find the equation of the straight line passing through the intersection of x+2y-3=0 and 3x+4y-7=0 and perpendicular to x+3y+4=0

Classify the following pairs of lines as coincident,parallel or intersecting: x+2y-3=0 and -3x-6y+9=0x+2y+1=0 and 2x-4y+3=03x-2y+5=0 and 2x+y-9=0

Which of the st.lines 2x-y+3=0 and x-4y-7=0 is farther from the origin ?

Which of the st.lines 2x-y+3=0 and x-4y-7=0 is farther from the origin ?

Solve:(1)/(2(2x+3y))+(12)/(7(3x-2y))=(1)/(2)(7)/(2x+3y)+(4)/(3x-2y)=2 where 2x+3y!=0 and 3x-2y!=0

The equation of straight line belonging to both the families of lines (x-y+1)+lambda_1(2x-y-2)=0 and (5x+3y-2)+lambda_2(3x-y-4)=0 where lambda_1, lambda_2 are arbitrary numbers is (A) 5x -2y -7=0 (B) 2x+ 5y - 7= 0 (C) 5x + 2y -7 =0 (D) 2x- 5y- 7= 0

The straight lines 4x-3y-5=0, x-2y=0, 7x+y-40=0 and x+3y+10=0 from