`2x+y=5` and `3x-2y=4`

Two adjacent sides of a rhombus are 2x+3y=a-5 and 3x+2y=4-2a and its diagonals intersect at the point (1,2) then a can be

If 2x+3y=5 and 3x+2y=10 then x-y= (a) 3 (b) 4 (c) 5 (d) 6

If the equations of the diagonals of the parallelogram formed by the lines,2x-y+7=0;2x-y-5=0;3x+2y-5=0 and 3x+2y+4=0 are ax+by-5=0 and px+qy+1=0. Find the value of (a+b+p+q)

If A=((2,-3,5),(3,2,-4),(1,1,-2)) find A^(-1). Use it to solve the system of equations 2x-3y+5z=11 , 3x+2y-4z=-5 and x+y-2z=-3

Consider the family of line (x+y-1)+lamda(2x+3y-5)=0 and (3x+2y-4)+mu(x+2y-6)=0 Equation of a straight line that belongs to both the families is:

Consider the family of lines (x+y-1)+lambda(2x+3y-5)=0 and (3x+2y-4)+mu(x+2y-6)=0 Equation of a line that belongs to both the family is (A) x-2y-8=0 (B) x-2y+8=0 (C) 2x+y-8=0 (D) 2x-y-8=0

Consider the family of lines (x+y-1)+lambda(2x+3y-5)=0 and (3x+2y-4)+mu(x+2y-6)=0 Equation of a line that belongs to both the family is (A) x-2y-8=0 (B) x-2y+8=0 (C) 2x+y-8=0 (D) 2x-y-8=0

Subtract the sum of - 3x^3y^2 + 2x^2 y^3 and - 3x^2y^3 - 5y^4 " from " x^4 + x^3y^2 + x^2y^3 + y^4