`3x-2y=1` and `2x+5y=3`

The area of triangle formed by the lines 2x-y+1=0 , 3x-y+5=0 and 2x-5y+11=0

Using substitution method solve for x and y : 3x+5y=10 and 2x-y=2 .

If 3x + 5y = 21 and 2x +3y = 13 , then find the values of x and y .

3x+2y=4 ; & 8x+5y=9

The equation of the transvers and conjugate axes of a hyperbola are,respectively,x+2y-3=0 and 2x-y+4=0, and their respective lengths are sqrt(2) and 2sqrt(3) .The equation of the hyperbola is (2)/(5)(x+2y-3)^(2)-(3)/(5)(2x-y+4)^(2)=1(2)/(5)(x-y-3)^(2)-3(x+2y-3)^(2)=12(x+2y-3)^(2)-3(2x-y+4)^(2)=1

Let real numbers x and y satisfy the equations x^(3)-3x^(2)+5x=1 and y^(3)-3y^(2)+5y=5 respectively then the value of x+y is equal to

The equation of the line which intersect each of the two lines 2x+y-1 =0 =x-2y+3z and 3x -y+z+2 = 0 = 4x + 5y - 2z-3 = 0 and is parallel to (x)/(1)=(y)/(2)=(z)/(3) is

Solve the system of equations 2x+5y=1 and 3x+2y=7