`sin^2theta-cos^2phi=sin^2phi-cos^2theta`

If theta+phi+psi=2pi, prove that cos^2theta+cos^2phi+cos^2psi -2costheta cosphi cospsi=1

cos2thetacos2phi+sin^2(theta-phi)-sin^2(theta+phi)=

Prove the following identities: 2(sin^6theta+cos^6theta)-3(sin^4theta+cos^4theta)+1=0 sin^6theta+cos^6theta+3sin^2thetacos^2theta=1 (sin^8theta-cos^8theta)=(sin^2theta-cos^2theta)(1-2s in^2thetacos^2theta)

If sintheta+sin^2theta=1, then prove that cos^(12)theta+3cos^(10)theta+3cos^8theta+cos^6theta-1=0 Given that sintheta=1-sin^2theta=1-sin^2theta=cos^2theta

(1+sin2theta+cos2theta)/(1+sin2theta-cos2theta)=?

Prove : (1+sin2theta-cos2theta)/(1+sin2theta+cos2theta)=tantheta

The product of matrices A=[[cos^2theta,sinthetacostheta],[sinthetacostheta,sin^2theta]] and B=[[cos^2phi,sinphicosphi],[sinphicosphi,sin^2phi]] is a null matrix if theta-phi= (A) 2npi,n in Z (B) (npi)/2, n in Z (C) (2n+1)pi/2, n in Z (D) npi, n in Z

Prove that cos^6 theta+ sin^6 theta= 1-3sin^2 theta cos^2 theta

If sin 2theta+sin 2phi=1//2 and cos2theta+cos 2phi=3//2 , then cos^(2)(theta-phi)=

if determinant |{:( cos (theta + phi),,-sin (theta+phi),,cos 2phi),(sin theta,,cos theta,,sin phi),(-cos theta,,sintheta,,cos phi):}| is