`a) 2 frac{1}{4}+3 frac{1}{6} b) 2frac{7}{12}+3frac{1}{12}+4frac{1}{12}`

If the shortest distance between the lines frac{x - lambda} {-2} = frac{y - 2} {1} = frac{z - 1} {1} and frac{x - sqrt 3}{1} = frac{y-1}{-2} = frac{z-2}{1} is 1, then the sum of all possible values of lambda is :

Determine the term independent of a in the expansion of (frac{a+1}{a^frac{2}{3}-a^frac{1}{3}+1)-frac{a-1}{a-a^frac{1}{2}))^10

Add the following: 3frac{1}{13} + 1frac{4}{13} + 2frac{3}{13}

2.Simplify 1frac{3}{4}xx2frac{2}{5}xx3frac{4}{7}

2.Simplify 1frac{3}{4}xx2frac{2}{5}xx3frac{4}{7}

Find the value of : (2frac{2}{3}).(2frac{1}{5})

The value of frac(2frac(1)(3) xx 4frac(1)(4) -4frac(1)(6) + 6 frac(1)(4)) (3frac(1)(3) + 4frac(1)(4) xx 5frac(2)(3)) is (A) 21frac(1)(160) (B) 2frac(13)(160 (C ) 2frac(21)(160) (D) frac(7)(1000)

What is the correct ascending order for the given fractions? (A) frac(22)(7) , frac(13)(17) , frac(11)(19) , frac(2)(3) , (B) frac(11)(19) , frac(2)(3) , frac(13)(17) , frac(22)(7) , (C ) frac(2)(3) , frac(11)(19) , frac(13)(17) , frac(22)(7) (D) frac(2)(3) , frac(13)(17) , frac(11)(19) , frac(22)(7) .

Find the coefficient of x^n in the expansion of (1+frac{x}{1!}+frac{x^2}{2!}+frac{x^3}{3!}+...+frac{x^n}{n!})^2 .