`(1-sin theta-cos theta)/(sin theta-1-cos theta)=(sin theta)/(1+cos theta)`

(1+sin2theta+cos2theta)/(1+sin2theta-cos2theta)=?

(1+sin 2theta+cos 2theta)/(1+sin2 theta-cos 2 theta) =

cos theta=sqrt(1-sin theta)

cos theta=sqrt(1-sin theta)

int (d theta)/((sin theta - 2 cos theta)(2 sin theta + cos theta))

If u=(1+cos theta)(1+cos 2theta)-sin theta.sin 2theta, v=sin theta(1+cos 2theta)+sin 2theta(1+cos theta) , then u^(2)+v^(2)=

(sin theta)/(cos3theta)+(sin3theta)/(cos9theta)+(sin9theta)/(cos27theta)+(sin27theta)/(cos81theta)=

Prove that (cos^3theta+sin^3 theta)/(cos theta+sin theta)+(cos^3 theta-sin^3 theta)/(cos theta-sin theta)=2

If k_1=tan 27 theta-tan theta and k_2=(sintheta)/(cos3theta)+(sin3theta)/(cos9theta)+(sin9theta)/(cos27theta) then,

Prove that : (cos theta)/(1-tan theta) + (sin theta)/(1-cot theta) = sin theta + cos theta