`frac{1}{2}sin^2 theta + frac{1}{3} cos^2 theta`

The maximum value of the expression 1/(sin^2 theta + 3 sin theta cos theta + 5cos^2 theta) is

The maximum value of the expression 1/(sin^2 theta + 3 sin theta cos theta + 5cos^2 theta) is

sin^-1 (sin frac {2pi}3 )

If sintheta+sin^2theta=1 , prove that cos^2theta+cos^4theta=1

Prove that cos^6 theta+ sin^6 theta= 1-3sin^2 theta cos^2 theta

If sintheta+sin^2theta=1, then prove that cos^(12)theta+3cos^(10)theta+3cos^8theta+cos^6theta-1=0 Given that sintheta=1-sin^2theta=1-sin^2theta=cos^2theta

If |(1+sin^2 theta,sin^2 theta,sin^2 theta),(cos^2 theta,1+cos^2 theta,cos^2 theta),(4sin 4 theta,4sin4theta,1+4sin4theta)|=0, then ... sin 4theta equal to ....

(sin theta + sin 2 theta)/( 1 + cos theta + cos 2 theta) = tan theta.

Prove that ((1+cot theta +tan theta)(sin theta - cos theta))/(sec ^3 theta -cosec^3 theta) = sin^2 theta cos^2 theta.

sin^(3)theta + sin theta - sin theta cos^(2)theta =